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m-2-4m-4-m-2n-8-1-4-0-n-




Question Number 182999 by Shrinava last updated on 18/Dec/22
(√(m^2 −4m+4)) + ((m−2n+8))^(1/4)  = 0  n = ?
$$\sqrt{\mathrm{m}^{\mathrm{2}} −\mathrm{4m}+\mathrm{4}}\:+\:\sqrt[{\mathrm{4}}]{\mathrm{m}−\mathrm{2n}+\mathrm{8}}\:=\:\mathrm{0} \\ $$$$\mathrm{n}\:=\:? \\ $$
Answered by cortano1 last updated on 18/Dec/22
 ∣m−2∣ +((m−2n+8))^(1/4)  = 0    { ((m=2)),((((10−2n))^(1/4)  = 0 ⇒n=5 )) :}
$$\:\mid{m}−\mathrm{2}\mid\:+\sqrt[{\mathrm{4}}]{{m}−\mathrm{2}{n}+\mathrm{8}}\:=\:\mathrm{0} \\ $$$$\:\begin{cases}{{m}=\mathrm{2}}\\{\sqrt[{\mathrm{4}}]{\mathrm{10}−\mathrm{2}{n}}\:=\:\mathrm{0}\:\Rightarrow{n}=\mathrm{5}\:}\end{cases} \\ $$

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