m-2-n-2-6-n-m-m-2-6-n-2-m-n-12-

Question Number 114134 by sherzodbek last updated on 17/Sep/20

(m^{2} - n^{2} + 6 (n + m) / (m^{2} - {(6 - n)}^{2}

m + n = 12

Commented by sherzodbek last updated on 17/Sep/20

yes

Commented by bemath last updated on 17/Sep/20

d o y o u m e a n t \frac{m^{2} - n^{2} + 6 (n + m)}{m^{2} - {(6 - n)}^{2}} ?

w h e r e m + n = 12

Commented by bemath last updated on 17/Sep/20

\Leftrightarrow \frac{12 (m - n) + 72}{(m + 6 - n) (m + n - 6)} =

\frac{12 (m - n) + 72}{(m - n + 6) (6)} = \frac{2 (m - n) + 12}{m - n + 6}

= \frac{2 (12 - n - n) + 12}{12 - n - n + 6}

= \frac{36 - 4 n}{18 - 2 n} = \frac{2 (18 - 2 n)}{18 - 2 n} = 2

Commented by MJS_new last updated on 17/Sep/20

\frac{m^{2} - n^{2} + 6 (n + m)}{m^{2} - {(6 - n)}^{2}} = \frac{m + n}{m + n - 6} = 2

Answered by sherzodbek last updated on 17/Sep/20

Commented by mathmax by abdo last updated on 18/Sep/20

really good for somebody \dots .