Question Number 144424 by Engr_Jidda last updated on 25/Jun/21
$${make}\:{c}\:{the}\:{subject}\:{in}\:{S}=\frac{\mathrm{1}}{\mathrm{2}\left({a}+{b}+{c}\right)} \\ $$
Answered by ajfour last updated on 25/Jun/21
$$\:{c}=−\left({a}+{b}\right)\:\:\: \\ $$$${or}\:\:{c}=\frac{\mathrm{1}}{\mathrm{2}{S}}−\left({a}+{b}\right) \\ $$
Answered by MJS_new last updated on 25/Jun/21
$${S}=\frac{\mathrm{1}}{\mathrm{2}\left({a}+{b}+{c}\right)} \\ $$$$\mathrm{2}\left({a}+{b}+{c}\right){S}=\mathrm{1} \\ $$$${a}+{b}+{c}=\frac{\mathrm{1}}{\mathrm{2}{S}} \\ $$$${c}=\frac{\mathrm{1}}{\mathrm{2}{S}}−\left({a}+{b}\right) \\ $$