make-r-the-subject-of-the-relation-m-4-u-r-v-r-

Question Number 55240 by Otchere Abdullai last updated on 19/Feb/19

m a k e r t h e s u b j e c t o f t h e r e l a t i o n

m = \frac{4 \sqrt{u + r}}{v - r}

Answered by MJS last updated on 20/Feb/19

m (v - r) = 4 \sqrt{u + r}

squaring both sides

m^{2} {(v - r)}^{2} = 16 (u + r)

expand for r

m^{2} r^{2} - 2 (m^{2} v + 8) r + m^{2} v^{2} - 16 u = 0

solve with formula for 2^{nd} degree

r = \frac{8}{m^{2}} + v \pm \frac{4 \sqrt{m^{2} (u + v) + 4}}{m^{2}}

Commented by Otchere Abdullai last updated on 20/Feb/19

T h a n k y o u m j s s i r!