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Question Number 103300 by bramlex last updated on 14/Jul/20
many positive five−digit  integers with the first number 1  and there are three equal  numbers ?  (a) 810    (b) 720    (c)120  (d) 60     (e) 20
manypositivefivedigitintegerswiththefirstnumber1andtherearethreeequalnumbers?(a)810(b)720(c)120(d)60(e)20
Answered by bemath last updated on 14/Jul/20
case(1) 1_11xx =9×((4!)/(2!.2!)) = 54   case(2)1_11xy = C_2 ^9 ×((4!)/(2!)) = 432  case(3)1_xxxy = 9×8×((4!)/(3!)) = 288  case(4)1_1xxx= 9×((4!)/(3!))=36  totally = 54+432+288+36 = 810
case(1)1_11xx=9×4!2!.2!=54case(2)1_11xy=C29×4!2!=432case(3)1_xxxy=9×8×4!3!=288case(4)1_1xxx=9×4!3!=36totally=54+432+288+36=810
Commented by bemath last updated on 14/Jul/20
thank you
thankyou
Commented by john santu last updated on 14/Jul/20
correction   case(3) 1_xxxy = 9×8×((4!)/(3!)) =  288 .  totally = 54+432+288+36  =810. (answer A) (JS ⊛)
correctioncase(3)1_xxxy=9×8×4!3!=288.totally=54+432+288+36=810.(answerA)(JS)

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