n-1-11-1-n-1-4n-2-4n-n-1-please-help-

Question Number 112195 by 675480065 last updated on 06/Sep/20

\underset{n = 1}{\sum^{11}} \frac{{(- 1)}^{n + 1} (4 n + 2)}{4 n (n + 1)}

please help

Answered by MJS_new last updated on 06/Sep/20

simply calculate it! {it}^{'} s only the sum of 11

numbers \dots

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