n-1-m-log-n-n-3-2- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 63139 by Tawa1 last updated on 29/Jun/19 ∑mn=1lognn3/2 Commented by Tawa1 last updated on 30/Jun/19 pleasehelpwiththissirTestforconvergence.∑∞n=11n3sin2n Commented by Tawa1 last updated on 30/Jun/19 Godblessyousir Commented by mathmax by abdo last updated on 30/Jun/19 ifyouneedconvergenceletSm=∑n=1mln(n)n32wehavelimn→+∞Sm=∑n=2∞ln(n)n32letφ(x)=ln(x)x32withx>1wehaveφ′(x)=x32x−ln(x)32x12x3=x−32xln(x)x3=xx3{1−32ln(x)}⇒∃n0>0/forx>n0φisdecreazingon]x0,+∞[sotheserieand∫2+∞ln(x)x32dxhavethesamenaturebut∫2+∞ln(x)x32dx=ln(x)=t∫ln(2)+∞te32tetdt=∫ln(2)+∞te(1−32)tdt=∫ln(2)+∞te−t2dtthisintegralconvergesbecauselimt→+∞t2(te−t2)=0so∑n=1∞ln(n)n32converges. Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-128667Next Next post: lim-x-0-3tan-4x-12tan-x-3sin-4x-12sin-x- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.