Question Number 107263 by Dwaipayan Shikari last updated on 09/Aug/20
$$\underset{\mathrm{n}=\mathrm{1}} {\overset{\mathrm{n}} {\sum}}\sqrt{\mathrm{n}} \\ $$
Commented by Dwaipayan Shikari last updated on 09/Aug/20
$$\mathrm{Is}\:\mathrm{there}\:\mathrm{any}\:\mathrm{solution}? \\ $$