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n-1-sech-npi-n-




Question Number 130912 by Dwaipayan Shikari last updated on 30/Jan/21
Σ_(n=1) ^∞ ((sech(nπ))/n)
$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{{sech}\left({n}\pi\right)}{{n}} \\ $$

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