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n-c-r-1-n-c-r-n-1-c-r-solve-for-n-and-r-




Question Number 171845 by Mikenice last updated on 21/Jun/22
n_c_(r+1)  + n_c_r  =n+1_c_(r  .solve for  n and r.)
$${n}_{{c}_{{r}+\mathrm{1}} } +\:{n}_{{c}_{{r}} } ={n}+\mathrm{1}_{{c}_{{r}\:\:.{solve}\:{for}\:\:{n}\:{and}\:{r}.} } \\ $$

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