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N-is-completely-divisible-by-13-52-What-is-the-sum-of-the-digits-of-the-smallest-such-number-N-




Question Number 113001 by Aina Samuel Temidayo last updated on 10/Sep/20
N! is completely divisible by 13^(52) .  What is the sum of the digits of the  smallest such number N?
N!iscompletelydivisibleby1352.WhatisthesumofthedigitsofthesmallestsuchnumberN?
Commented by MJS_new last updated on 11/Sep/20
N!=13^(52) ×k  13! has 1 factor 13  (2×13)! has 2  (13k)! has k for k<13  (13^2 )! has 14  (13k)! has k+1 for k<26  (13×26)! has 28  (13k)! has k+2 for k<39  (13×39)! has 42  (13k)! has k+3 for k<52  ⇒ (13×49)! id divisible by 13^(52)   but I can′t calculate the sum of the digits of 637!
N!=1352×k13!has1factor13(2×13)!has2(13k)!haskfork<13(132)!has14(13k)!hask+1fork<26(13×26)!has28(13k)!hask+2fork<39(13×39)!has42(13k)!hask+3fork<52(13×49)!iddivisibleby1352butIcantcalculatethesumofthedigitsof637!

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