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n-n-1-n-2-n-3-n-r-1-




Question Number 41642 by Tawa1 last updated on 10/Aug/18
n(n − 1)(n − 2)(n − 3) .... (n − r + 1) = ??
n(n1)(n2)(n3).(nr+1)=??
Answered by alex041103 last updated on 10/Aug/18
=((n!)/((n−r)!))
=n!(nr)!
Commented by Tawa1 last updated on 10/Aug/18
please workings
pleaseworkings
Commented by alex041103 last updated on 10/Aug/18
n(n−1)...(n−r+1)=  =Π_(k=n−r+1) ^n k=Π_(k=n−r+1) ^n k ((Π_(k=1) ^(n−r) k)/(Π_(k=1) ^(n−r) k))=  =((Π_(k=1) ^n k)/(Π_(k=1) ^(n−r) k))=((n!)/((n−r)!))
n(n1)(nr+1)==nk=nr+1k=nk=nr+1knrk=1knrk=1k==nk=1knrk=1k=n!(nr)!
Commented by Tawa1 last updated on 10/Aug/18
God bless you sir
Godblessyousir

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