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n-o-oo-x-3n-2n-




Question Number 186689 by SANOGO last updated on 08/Feb/23
Σ_(n=o) ^(+oo)  (x^(3n) /((2n)!))  =   ?
+oon=ox3n(2n)!=?
Commented by mr W last updated on 08/Feb/23
why not ∞ instead of oo?  why not 0 instead of o?
whynotinsteadofoo?whynot0insteadofo?
Answered by mr W last updated on 08/Feb/23
e^x =1+x+(x^2 /(2!))+(x^3 /(3!))+(x^4 /(4!))+(x^5 /(5!))+...     (i)  e^(−x) =1−x+(x^2 /(2!))−(x^3 /(3!))+(x^4 /(4!))−(x^5 /(5!))+...     (ii)  (((i)+(ii))/2):  ((e^x +e^(−x) )/2)=1+(x^2 /(2!))+(x^4 /(4!))+...=Σ_(n=0) ^∞ (x^(2n) /((2n)!))  replace x with x^(3/2)   ((e^((3x)/2) +e^(−((3x)/2)) )/2)=Σ_(n=0) ^∞ (x^(3n) /((2n)!))  or  cosh (((3x)/2))=Σ_(n=0) ^∞ (x^(3n) /((2n)!))  ✓
ex=1+x+x22!+x33!+x44!+x55!+(i)ex=1x+x22!x33!+x44!x55!+(ii)(i)+(ii)2:ex+ex2=1+x22!+x44!+=n=0x2n(2n)!replacexwithx32e3x2+e3x22=n=0x3n(2n)!orcosh(3x2)=n=0x3n(2n)!

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