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nice-calculus-evaluate-0-pi-2-log-3-tan-x-dx-




Question Number 123255 by mnjuly1970 last updated on 24/Nov/20
          ∗∗∗  nice  calculus ∗∗∗         evaluate ::            Φ=∫_0 ^(π/2) log^3 (tan(x))dx =?
nicecalculusevaluate::Φ=0π2log3(tan(x))dx=?
Answered by Dwaipayan Shikari last updated on 24/Nov/20
∫_0 ^(π/2) log^3 (tanx)dx=I  =∫_0 ^(π/2) log^3 (cotx)=∫_0 ^(π/2) −log^3 (tanx)=I  2I=0⇒I=0
0π2log3(tanx)dx=I=0π2log3(cotx)=0π2log3(tanx)=I2I=0I=0
Commented by mnjuly1970 last updated on 24/Nov/20
   thank you...
thankyou

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