nice-calculus-number-theory-prove-thar-2-32-1-641-0-notice-without-calculator-and-only-with-the-u

Question Number 123287 by mnjuly1970 last updated on 24/Nov/20

\dots n i c e c a l c u l u s \dots

n u m b e r t h e o r y

p r o v e t h a r :::

2^{32} + 1 \overset{641}{\equiv} 0 ✓

n o t i c e : w i t h o u t c a l c u l a t o r a n d o n l y

w i t h t h e u s e o f c o n g r u e n c e p r o p e r t i e s . .

Answered by MJS_new last updated on 24/Nov/20

just divide ?

I^{'} ve been having problems with proofs that

are easy to calculate \dots

2^{32} + 1 = 4 294 967 297 = 641 \times 6700417

maybe try to show that 2^{100} + 1 \equiv 0 (401) ?

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