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Question Number 123987 by mnjuly1970 last updated on 29/Nov/20
              ...nice   mathematics...     if    f(x)=x^3 +x  then           find   f^( −1) (x)=?
nicemathematicsiff(x)=x3+xthenfindf1(x)=?
Answered by MJS_new last updated on 29/Nov/20
y^3 +y−x=0  D=(1/(27))+(x^2 /4)>0∀x∈R  ⇒  f^(−1) (x)=(((x/2)+((√(3(27x^2 +4)))/(18))))^(1/3) −((−(x/2)+((√(3(27x^2 +4)))/(18))))^(1/3)
y3+yx=0D=127+x24>0xRf1(x)=x2+3(27x2+4)183x2+3(27x2+4)183
Commented by john_santu last updated on 30/Nov/20
Cardano
Cardano
Commented by MJS_new last updated on 30/Nov/20
yes
yes

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