Menu Close

Number-of-even-composite-factors-of-2520-




Question Number 175766 by BaliramKumar last updated on 06/Sep/22
Number of  even composite factors of 2520?
Numberofevencompositefactorsof2520?
Commented by mr W last updated on 06/Sep/22
2520=2^3 ×3^2 ×5×7  for even factors 2 must be contained  at least one time, 2520 must be excluded.  ⇒3×3×2×2−1=35
2520=23×32×5×7forevenfactors2mustbecontainedatleastonetime,2520mustbeexcluded.3×3×2×21=35
Answered by aleks041103 last updated on 06/Sep/22
let s(n) be the number of composite factors  of n.  let n=p_1 ^r_1  p_2 ^r_2  ...p_k ^r_k  , where p_(1,2,..,k)  are primes  and r_(1,2,...,k) ∈N={1,2,...}  any factor f of n must be of the form:  f=p_1 ^t_1  p_2 ^t_2  ...p_k ^t_k  , where 0≤t_i ≤r_i .  ⇒ for t_i  we have r_i +1 possibilities.  ⇒#factors of n=Π_(i=1) ^k (1+r_i )=σ(n)  out of those σ(n) factors the noncomposite  are 1,p_1 ,p_2 ,...,p_k , i.e. k+1.  ⇒s(n)=σ(n)−k−1  ⇒s(n)=[Π_(i=1) ^k (1+r_i )]−k−1  Now, the composite factors are 2 types  devisible by p_q  and not devisible by p_q .  The ones not devisible by p_q  are all the   composite factors of  (n/p_q ^r_q  )  ⇒The answer is:  s(n)−s((n/p_q ^r_q  ))= { (([r_q Π_(i=1,i≠q) ^k (1+r_i )]−1 , p_q ∣n)),(([r_q Π_(i=1,i≠q) ^k (1+r_i )] , p_q ∤n)) :}  in our case:  2520=2.5.2.2.7.9=2^3 .3^2 .5.7  ⇒ ans.=3(2+1)(1+1)(1+1)−1=  =3.3.2.2−1=35  ⇒Ans. 35
lets(n)bethenumberofcompositefactorsofn.letn=p1r1p2r2pkrk,wherep1,2,..,kareprimesandr1,2,,kN={1,2,}anyfactorfofnmustbeoftheform:f=p1t1p2t2pktk,where0tiri.fortiwehaveri+1possibilities.You can't use 'macro parameter character #' in math modeoutofthoseσ(n)factorsthenoncompositeare1,p1,p2,,pk,i.e.k+1.s(n)=σ(n)k1s(n)=[ki=1(1+ri)]k1Now,thecompositefactorsare2typesdevisiblebypqandnotdevisiblebypq.TheonesnotdevisiblebypqareallthecompositefactorsofnpqrqTheansweris:s(n)s(npqrq)={[rqki=1,iq(1+ri)]1,pqn[rqki=1,iq(1+ri)],pqninourcase:2520=2.5.2.2.7.9=23.32.5.7ans.=3(2+1)(1+1)(1+1)1==3.3.2.21=35Ans.35
Commented by aleks041103 last updated on 06/Sep/22
Commented by mr W last updated on 06/Sep/22
2 is valid, 2520 invalid?
2isvalid,2520invalid?
Commented by BaliramKumar last updated on 06/Sep/22
thanks
thanks
Commented by aleks041103 last updated on 07/Sep/22
Well 2 is even but not composite, while  2520 is both even and composite and also  is a factor of itself.  So 2 doesn′t count, while 2520 counts.
Well2isevenbutnotcomposite,while2520isbothevenandcompositeandalsoisafactorofitself.So2doesntcount,while2520counts.

Leave a Reply

Your email address will not be published. Required fields are marked *