Menu Close

number-of-real-solution-of-equation-a-2008-b-2008-2008ab-2006-




Question Number 16047 by vpawarksp@gmail.com last updated on 17/Jun/17
number of real solution of equation    a^(2008)  +  b^(2008)   = 2008ab−2006
$${number}\:{of}\:{real}\:{solution}\:{of}\:{equation}\:\:\:\:{a}^{\mathrm{2008}} \:+\:\:{b}^{\mathrm{2008}} \:\:=\:\mathrm{2008}{ab}−\mathrm{2006}\:\:\:\:\:\:\:\:\: \\ $$
Commented by Tinkutara last updated on 17/Jun/17
You can verify that a = b = 1 satisfy  the equation.
$$\mathrm{You}\:\mathrm{can}\:\mathrm{verify}\:\mathrm{that}\:{a}\:=\:{b}\:=\:\mathrm{1}\:\mathrm{satisfy} \\ $$$$\mathrm{the}\:\mathrm{equation}. \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *