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Question Number 165385 by SLVR last updated on 31/Jan/22
Number of  ways..n   differrnt  things be distributed  in r identical boxes so as  1)empty box is allowed  2)empty box not allowed  Number of ways...n identical  things be distributed to r  identical boxes so as  1)empty box allowed  2)empty box not allowed
Numberofways..ndifferrntthingsbedistributedinridenticalboxessoas1)emptyboxisallowed2)emptyboxnotallowedNumberofwaysnidenticalthingsbedistributedtoridenticalboxessoas1)emptyboxallowed2)emptyboxnotallowed
Commented by SLVR last updated on 31/Jan/22
kindly...provide proof   if  possible
kindlyprovideproofifpossible
Answered by mr W last updated on 01/Feb/22
I.  n different objects into r identical  boxes  a) non empty box   S(n,r) ←stirling number of the second kind  b) empty box allowed  S(n,1)+S(n,2)+...+S(n,r)    II.  n identical objects into r identical  a) non empty box  p(n,r) ←number of partions of n into r parts  b) empty box allowed  p(n,1)+p(n,2)+...+p(n,r)
I.ndifferentobjectsintoridenticalboxesa)nonemptyboxS(n,r)stirlingnumberofthesecondkindb)emptyboxallowedS(n,1)+S(n,2)++S(n,r)II.nidenticalobjectsintoridenticala)nonemptyboxp(n,r)numberofpartionsofnintorpartsb)emptyboxallowedp(n,1)+p(n,2)++p(n,r)
Commented by SLVR last updated on 02/Feb/22
So kind of you sir...we are blessed  Here i am new to S(n,r) and   i tried with Google search..  but i could not get through..  kidly explain S(9,5) and S(5,3)  also p(n,r) with p(5,3).Kindly  bless me sir...
SokindofyousirweareblessedHereiamnewtoS(n,r)anditriedwithGooglesearch..buticouldnotgetthrough..kidlyexplainS(9,5)andS(5,3)alsop(n,r)withp(5,3).Kindlyblessmesir
Commented by mr W last updated on 02/Feb/22
https://en.m.wikipedia.org/wiki/Stirling_numbers_of_the_second_kind
Commented by mr W last updated on 02/Feb/22
https://en.m.wikipedia.org/wiki/Partition_(number_theory)
Commented by SLVR last updated on 06/Feb/22
So kind of you prof.W...God bless you
Sokindofyouprof.WGodblessyou

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