Menu Close

Obtain-a-general-formula-for-the-sequence-2-3-4-5-8-9-16-17-32-33-assuming-the-sequence-continues-in-that-pattern-




Question Number 165361 by MikeH last updated on 31/Jan/22
Obtain a general formula for  the sequence   (2/3),(4/5),(8/9),((16)/(17)),((32)/(33)),...  assuming the sequence continues in that  pattern.
Obtainageneralformulaforthesequence23,45,89,1617,3233,assumingthesequencecontinuesinthatpattern.
Commented by MJS_new last updated on 31/Jan/22
((7n^4 )/(33660))−((13n^3 )/(16830))−((767n^2 )/(33660))+((3433n)/(16830))+((818)/(1683))
7n43366013n316830767n233660+3433n16830+8181683
Commented by MJS_new last updated on 31/Jan/22
you can like or dislike it but it still is one  of zillions of right answers
youcanlikeordislikeitbutitstillisoneofzillionsofrightanswers
Answered by Rasheed.Sindhi last updated on 31/Jan/22
 (2/3),(4/5),(8/9),((16)/(17)),((32)/(33)),...  (2/(2+1)),(4/(4+1)),(8/(8+1)),((16)/(16+1)),((32)/(32+1)),...  (2^1 /(2^1 +1)),(2^2 /(2^2 +1)),(2^3 /(2^3 +1)),(2^4 /(2^4 +1)),(2^5 /(2^5 +1)),...,(2^n /(2^n +1))
23,45,89,1617,3233,22+1,44+1,88+1,1616+1,3232+1,2121+1,2222+1,2323+1,2424+1,2525+1,,2n2n+1

Leave a Reply

Your email address will not be published. Required fields are marked *