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odd-number-2n-1-The-sum-of-twelve-consecutive-natural-numbers-is-288-Find-the-largest-natural-number-




Question Number 187390 by mathlove last updated on 18/Feb/23
odd number (2n+1)  The sum of twelve consecutive natural numbers is 288. Find the largest natural number
oddnumber(2n+1)The sum of twelve consecutive natural numbers is 288. Find the largest natural number
Answered by JDamian last updated on 16/Feb/23
Does it really exist?    288=((12)/2)(n+n−11) ⇒   48=2n−11  n=((59)/2)  ∉  N  19+20+ ∙∙∙ +29+30=294  18+19+ ∙∙∙ +28+29=282
Doesitreallyexist?288=122(n+n11)48=2n11n=592N19+20++29+30=29418+19++28+29=282
Commented by mathlove last updated on 16/Feb/23
n=12  find a_n
n=12findan
Commented by JDamian last updated on 16/Feb/23
there is no such natural number a_n
Commented by MathsFan last updated on 17/Feb/23
thank you sir
thankyousir
Commented by mathlove last updated on 17/Feb/23
13+15+17+19+21+23+  25+27+29+31+33+35=288
13+15+17+19+21+23+25+27+29+31+33+35=288
Commented by mr W last updated on 17/Feb/23
then your question is wrong!
thenyourquestioniswrong!
Commented by JDamian last updated on 19/Feb/23
Mathlove, do you even check your questions and solutions before posting them?
Answered by HeferH last updated on 16/Feb/23
n + (n + 1) + (n + 2) + ... + (n + 11) = 288   12n + 1 + 2+...+11 = 288   12n + ((11(11 + 1))/2) = 288   12n = 288 − 66   n = ((222)/(12)) = ((37)/2) ∉ N
n+(n+1)+(n+2)++(n+11)=28812n+1+2++11=28812n+11(11+1)2=28812n=28866n=22212=372N
Commented by MathsFan last updated on 17/Feb/23
thanks a lot sir
thanksalotsir

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