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Question Number 181783 by mr W last updated on 30/Nov/22
one side of a triangle is 20 cm. the  other two sides are in ratio 1:3.  1) what is the maximum area of the  triangle, if exists?  2) what is the maximun perimeter  of the triangle, if exists?
onesideofatriangleis20cm.theothertwosidesareinratio1:3.1)whatisthemaximumareaofthetriangle,ifexists?2)whatisthemaximunperimeterofthetriangle,ifexists?
Answered by Frix last updated on 30/Nov/22
Let the sides x, 3x  5<x<10  The collapsed triangle 10,20,30 has the  maximum perimeter 60  The area is A(x)=2(√(−x^4 +125x^2 −2500))  A′(x)=((−4x(2x^2 −125))/(A(x)))=0∧5<x<10 ⇒ x=((5(√(10)))/2)  ⇒ maximum area is 75
Letthesidesx,3x5<x<10Thecollapsedtriangle10,20,30hasthemaximumperimeter60TheareaisA(x)=2x4+125x22500A(x)=4x(2x2125)A(x)=05<x<10x=5102maximumareais75
Commented by mr W last updated on 30/Nov/22
thanks sir!
thankssir!
Answered by MJS_new last updated on 30/Nov/22
generally for a given side a and a ratio  b:c=1:v with v>1 we get the maximum  area  ((a^2 v)/(2(v^2 −1))) with b=((√(v^2 +1))/(v^2 −1))a and c=vb
generallyforagivensideaandaratiob:c=1:vwithv>1wegetthemaximumareaa2v2(v21)withb=v2+1v21aandc=vb

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