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original-length-of-the-iron-rod-175-65-increase-6-1-3-175-65-19-3-1-100-175-65-19-175-65-3-100-3337-35-300-11-1245-new-length-original-length-increased-length-175-65-11-1245




Question Number 145437 by Saiki last updated on 04/Jul/21
original length of the iron rod=175.65  % increase=6(1/3)%×175.65  =((19)/3)×(1/(100))×175.65  =((19×175.65)/(3×100))=((3337.35)/(300))=11.1245  new length=original length+increased length  =175.65+11.1245  =186.7745cm  solution by CASIO.....
$${original}\:{length}\:{of}\:{the}\:{iron}\:{rod}=\mathrm{175}.\mathrm{65} \\ $$$$\%\:{increase}=\mathrm{6}\frac{\mathrm{1}}{\mathrm{3}}\%×\mathrm{175}.\mathrm{65} \\ $$$$=\frac{\mathrm{19}}{\mathrm{3}}×\frac{\mathrm{1}}{\mathrm{100}}×\mathrm{175}.\mathrm{65} \\ $$$$=\frac{\mathrm{19}×\mathrm{175}.\mathrm{65}}{\mathrm{3}×\mathrm{100}}=\frac{\mathrm{3337}.\mathrm{35}}{\mathrm{300}}=\mathrm{11}.\mathrm{1245} \\ $$$${new}\:{length}={original}\:{length}+{increased}\:{length} \\ $$$$=\mathrm{175}.\mathrm{65}+\mathrm{11}.\mathrm{1245} \\ $$$$=\mathrm{186}.\mathrm{7745}{cm} \\ $$$${solution}\:{by}\:{CASIO}….. \\ $$$$ \\ $$

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