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p-1-1-2-1-3-1-4-1-2003-1-2004-q-1-1003-1-1004-1-2004-p-2-q-2-




Question Number 91277 by john santu last updated on 29/Apr/20
p=1−(1/2)+(1/3)−(1/4)+...+(1/(2003))−(1/(2004))  q=(1/(1003))+(1/(1004))+...+(1/(2004))  p^2 +q^2  =
p=112+1314++1200312004q=11003+11004++12004p2+q2=
Answered by naka3546 last updated on 30/Apr/20
Commented by jagoll last updated on 30/Apr/20
i think it wrong answer
ithinkitwronganswer
Commented by naka3546 last updated on 30/Apr/20
Show  your  workings, please
Showyourworkings,please
Answered by naka3546 last updated on 30/Apr/20

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