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P-i-2-R-then-how-dP-P-2-dI-I-Similarly-P-V-2-R-then-how-dP-P-2-dV-V-




Question Number 36707 by rahul 19 last updated on 04/Jun/18
P=i^2 R then how (dP/P) = 2 (dI/I) ?  Similarly P= (V^2 /R) then how (dP/P)=2(dV/V)?
P=i2RthenhowdPP=2dII?SimilarlyP=V2RthenhowdPP=2dVV?
Commented by rahul 19 last updated on 04/Jun/18
On differentiating we get,  dP= 2IdI×R .
Ondifferentiatingweget,dP=2IdI×R.
Answered by tanmay.chaudhury50@gmail.com last updated on 04/Jun/18
P=I^2 R  (dP/dI)=2IR  dP=2IRdI  (dP/P)=((2IRdI)/(I^2 R))  (dP/P)=((2dI)/I)  proved
P=I2RdPdI=2IRdP=2IRdIdPP=2IRdII2RdPP=2dIIproved
Commented by rahul 19 last updated on 04/Jun/18
thanks sir.
thankssir.
Answered by tanmay.chaudhury50@gmail.com last updated on 04/Jun/18
P=(V^2 /R)  (dP/dV)=((2V)/R)  dP=((2VdV)/R)  (dP/P)=((2VdV×R)/(R×V^2 ))  (dP/P)=((2dV)/V) proved
P=V2RdPdV=2VRdP=2VdVRdPP=2VdV×RR×V2dPP=2dVVproved

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