p-is-a-polynomial-having-n-roots-x-i-with-x-i-x-j-for-i-j-prove-that-i-1-n-p-x-i-p-x-i-0-

Question Number 29832 by abdo imad last updated on 12/Feb/18

p i s a p o l y n o m i a l h a v i n g n r o o t s x_{i} w i t h x_{i} \neq x_{j} f o r i \neq j

p r o v e t h a t \sum_{i = 1}^{n} \frac{p^{^{″}} (x_{i})}{p^{^{'}} (x_{i})} = 0