p-is-a-polynomial-having-n-simples-roots-x-i-1-i-n-prove-that-k-1-n-1-p-x-k-0-

Question Number 32331 by abdo imad last updated on 23/Mar/18

p i s a p o l y n o m i a l h a v i n g n s i m p l e s r o o t s {(x_{i})}_{1 ⩽ i ⩽ n}

p r o v e t h a t \sum_{k = 1}^{n} \frac{1}{p^{^{'}} (x_{k})} = 0