Question Number 147473 by Sanvi2007 last updated on 21/Jul/21
$${p}\left({t}\right)=\mathrm{4}{t}^{\mathrm{4}} +\mathrm{5}{t}^{\mathrm{3}} −{t}^{\mathrm{2}} +\mathrm{6}\:\:{at}\:\:{t}={a} \\ $$
Commented by physicstutes last updated on 21/Jul/21
$$\mathrm{at}\:{t}\:=\:{a}\:,\:{p}\left({a}\right)\:=\:\mathrm{4}{a}^{\mathrm{4}} +\mathrm{5}{a}^{\mathrm{3}} −{a}^{\mathrm{2}} +\mathrm{6} \\ $$