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P-X-299-318-standard-deviation-42-P-z-299-318-42-P-z-0-45-Is-it-P-z-0-45-P-0-45-lt-z-lt-0-44-If-not-how-to-find-P-z-0-45-




Question Number 23781 by alibhar last updated on 06/Nov/17
P(X=299), μ=318, standard deviation=42  P(z=((299−318)/(42)))  P(z=−0.45)    Is it P(z=−0.45)=P(−0.45<z<−0.44)?    If not, how to find P(z=−0.45)?
P(X=299),μ=318,standarddeviation=42P(z=29931842)P(z=0.45)IsitP(z=0.45)=P(0.45<z<0.44)?Ifnot,howtofindP(z=0.45)?

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