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p-x-2x-2-4x-2-pq-4-and-p-q-2-faind-p-a-2-q-a-1-




Question Number 176327 by mathlove last updated on 16/Sep/22
p(x)=2x^2 +(√(4x^2 ))     pq=4    and  p+q=2   faind  p^a_2  +q^a_1  =?
$${p}\left({x}\right)=\mathrm{2}{x}^{\mathrm{2}} +\sqrt{\mathrm{4}{x}^{\mathrm{2}} }\:\:\: \\ $$$${pq}=\mathrm{4}\:\:\:\:{and}\:\:{p}+{q}=\mathrm{2}\:\:\:{faind} \\ $$$${p}^{{a}_{\mathrm{2}} } +{q}^{{a}_{\mathrm{1}} } =? \\ $$

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