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P-x-3-x-2-x-5-x-P-1-

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Question Number 172842 by cortano1 last updated on 02/Jul/22
P(x^3 −x^2 ) = x^(5 ) + x P(−1)=?
P(x3−x2)=x5+xP(−1)=?
Commented by greougoury555 last updated on 02/Jul/22
⇒x^3 −x^2 =−1 ; x^3 =x^2 −1 ⇒x^4 = x^3 −x = x^2 −x−1 ⇒x^5 = x^3 −x^2 −x ⇒x^5 +x = x^2 −1−x^2 =−1 ∴ P(−1)= −1
⇒x3−x2=−1;x3=x2−1⇒x4=x3−x=x2−x−1⇒x5=x3−x2−x⇒x5+x=x2−1−x2=−1∴P(−1)=−1

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