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p-x-xp-x-x-2-1-faind-p-2-




Question Number 164135 by mathlove last updated on 14/Jan/22
p(x)+xp(−x)=x^2 +1  faind   p(2)=?
p(x)+xp(x)=x2+1faindp(2)=?
Answered by mr W last updated on 14/Jan/22
p(x)+xp(−x)=x^2 +1   ...(i)  p(−x)−xp(x)=x^2 +1  xp(−x)−x^2 p(x)=(x^2 +1)x   ...(ii)  (i)−(ii):  (1+x^2 )p(x)=(x^2 +1)(1−x)  ⇒p(x)=1−x  ⇒p(2)=1−2=−1
p(x)+xp(x)=x2+1(i)p(x)xp(x)=x2+1xp(x)x2p(x)=(x2+1)x(ii)(i)(ii):(1+x2)p(x)=(x2+1)(1x)p(x)=1xp(2)=12=1
Commented by mathlove last updated on 14/Jan/22
thanks   thear mr W
thanksthearmrW
Commented by mathlove last updated on 14/Jan/22
Commented by mr W last updated on 14/Jan/22
look above again!
lookaboveagain!
Commented by mathlove last updated on 14/Jan/22
thank   I know
thankIknow

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