par-recurence-4-n-2n-lt-n-k-lt-4-n-2-

Question Number 163836 by SANOGO last updated on 11/Jan/22

$${par}\:{recurence} \\ $$$$\frac{\mathrm{4}^{{n}} }{\mathrm{2}{n}}<\left(_{{n}} ^{{k}} \right)<\frac{\mathrm{4}^{{n}} }{\mathrm{2}} \\ $$