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pi-2-2pi-3-argshx-2-2cosx-dx-




Question Number 127715 by snipers237 last updated on 01/Jan/21
 ∫_(π/2) ^((2π)/3)   (((argshx)^2 )/(2cosx)) dx = ?
π22π3(argshx)22cosxdx=?

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