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pi-2-pi-2-dx-1-e-sin-x-




Question Number 89946 by jagoll last updated on 20/Apr/20
∫ _(−(π/2)) ^(π/2)  (dx/(1+e^(sin x) ))
π2π2dx1+esinx
Answered by john santu last updated on 20/Apr/20
I = ∫_((−π)/2) ^(π/2)  ((dx/(1+e^(sin x) )))   replace x by −x   I = ∫_(π/2) ^(−(π/2))  (((−dx)/(1+e^(−sin x) ))) = ∫_(−(π/2)) ^(π/2) ((dx/(1+e^(−sin x) )))  I+I = ∫_(−(π/2)) ^(π/2)  ((1+e^(sin x) )/(1+e^(sin x) )) dx  2I = ∫_(−(π/2)) ^(π/2)  1dx = π  I = (π/2)
I=π2π2(dx1+esinx)replacexbyxI=π2π2(dx1+esinx)=π2π2(dx1+esinx)I+I=π2π21+esinx1+esinxdx2I=π2π21dx=πI=π2

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