pi-2-pi-2-sin-x-dx-pi-0-cos-x-dx- Tinku Tara June 4, 2023 None 0 Comments FacebookTweetPin Question Number 156240 by SANOGO last updated on 09/Oct/21 ∫−π2π2∣sin(x)∣dx∫0π∣cos(x)∣dx Commented by SANOGO last updated on 09/Oct/21 mercibienledur Commented by tabata last updated on 09/Oct/21 youarewelcome Commented by tabata last updated on 09/Oct/21 ∫−π2π2∣sin(x)∣dx∣sin(x)∣isalwaysevenfunctionandsymetricaboutzero∴∫−π2π2∣sin(x)∣dx=2∫0π2∣sin(x)∣dxI=−2(cos(x))0π2=−2(−1)=2when:∫0π∣cos(x)∣dxalso=2⟨M.T⟩ Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: sin-2-7pi-8-sin-2-3pi-8-sin-2-5pi-8-sin-2-pi-8-Next Next post: Question-90706 Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.