pi-e-sin-1-pi-2-2e-2-sin-2-pi-3-3e-3-sin-3-pi-4-4e-4-sin-4-

Question Number 130415 by Dwaipayan Shikari last updated on 25/Jan/21

\frac{π}{e} s i n (1) - \frac{π^{2}}{2 e^{2}} s i n (2) + \frac{π^{3}}{3 e^{3}} s i n (3) - \frac{π^{4}}{4 e^{4}} s i n (4) + \dots

Commented by Dwaipayan Shikari last updated on 25/Jan/21

{t a n}^{- 1} (\frac{π s i n (1)}{π c o s (1) + e})

B u t i a m n o t s u r e