pi-pi-sin-x-cos-x-dx- Tinku Tara June 4, 2023 Integration 0 Comments FacebookTweetPin Question Number 95227 by bobhans last updated on 24/May/20 ∫π−π∣sinx+cosx∣dx=? Answered by john santu last updated on 24/May/20 Commented by john santu last updated on 24/May/20 ∫−π4−π(sinx+cosx)dx+∫3π4−π4(sinx+cosx)dx+∫π3π4(sinx+cosx)dx=2∫3π4−π4(sinx+cosx)dx=2[−cosx+sinx]−π43π4=2{2−(−2)}=42 Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: sin-10-sin-20-sin-30-sin-40-sin-360-Next Next post: 0-pi-2-cos-2-x-cos-2-x-4sin-2-x-dx- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.