please-can-you-help-me-with-this-caculus-1-cos-2-x-dx-

Question Number 52233 by de best last updated on 04/Jan/19

p l e a s e c a n y o u h e l p m e w i t h t h i s

c a c u l u s : \int \frac{1}{{c o s}^{2} x} d x

Answered by MJS last updated on 04/Jan/19

this is a standard integral

f (x) = \tan x

f^{'} (x) = \frac{1}{\cos^{2} x}

\Rightarrow \int \frac{d x}{\cos^{2} x} = \tan x + C

Answered by peter frank last updated on 04/Jan/19

\int {s e c}^{2} x d x = \tan x + G

Answered by peter frank last updated on 04/Jan/19

\int {s e c}^{2} x d x = \tan x + G