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Question Number 103597 by jimi last updated on 16/Jul/20
pls help solve this differential equation  (3x^2 sin ((1/x)) + y)dx = xcos((1/x)) −xdy
$$\boldsymbol{{pls}}\:\boldsymbol{{help}}\:\boldsymbol{{solve}}\:\boldsymbol{{this}}\:\boldsymbol{{differential}}\:\boldsymbol{{equation}} \\ $$$$\left(\mathrm{3}\boldsymbol{{x}}^{\mathrm{2}} \mathrm{sin}\:\left(\frac{\mathrm{1}}{\boldsymbol{{x}}}\right)\:+\:\boldsymbol{{y}}\right)\boldsymbol{{dx}}\:=\:\boldsymbol{{xcos}}\left(\frac{\mathrm{1}}{\boldsymbol{{x}}}\right)\:−\boldsymbol{{xdy}} \\ $$
Commented by OlafThorendsen last updated on 16/Jul/20
something is missing after xcos(1/x) ?
$$\mathrm{something}\:\mathrm{is}\:\mathrm{missing}\:\mathrm{after}\:{x}\mathrm{cos}\frac{\mathrm{1}}{{x}}\:? \\ $$
Commented by abdomathmax last updated on 16/Jul/20
perhaps the equation is  (3x^2 sin((1/x))+y)dx =(xcos((1/x))−x)dy
$$\mathrm{perhaps}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{is} \\ $$$$\left(\mathrm{3x}^{\mathrm{2}} \mathrm{sin}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)+\mathrm{y}\right)\mathrm{dx}\:=\left(\mathrm{xcos}\left(\frac{\mathrm{1}}{\mathrm{x}}\right)−\mathrm{x}\right)\mathrm{dy} \\ $$

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