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Question Number 43789 by Junaid555 last updated on 15/Sep/18
 plz solve it for me i am learning      (((81)/(125)))^(1/3)
plzsolveitformeiamlearning811253
Answered by MJS last updated on 15/Sep/18
((a/b))^(1/n) =((a)^(1/n) /( (b)^(1/n) ))     ((a×b))^(1/n) =(a)^(1/n) ×(b)^(1/n)   (c^n )^(1/n) =c  there are some exceptions but at this level  it′s good to remember these    (((81)/(125)))^(1/3) =(((81))^(1/3) /( ((125))^(1/3) ))=(((3×3×3×3))^(1/3) /( ((5×5×5))^(1/3) ))=(((3^3 ×3))^(1/3) /( (5^3 )^(1/3) ))=  =(((3^3 )^(1/3) ×(3)^(1/3) )/5)=(3/5)(3)^(1/3)
abn=anbna×bn=an×bncnn=ctherearesomeexceptionsbutatthislevelitsgoodtorememberthese811253=8131253=3×3×3×335×5×53=33×33533==333×335=3533
Commented by Junaid555 last updated on 15/Sep/18
Thank you very much
Thankyouverymuch

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