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Point-charges-88-C-55-C-and-70-C-are-placed-in-a-straight-line-The-central-one-is-0-75m-from-each-of-the-others-Calculate-the-net-force-on-each-due-to-the-other-two-




Question Number 39573 by NECx last updated on 08/Jul/18
Point charges 88μC,−55μC and  70μC are placed in a straight line.  The central one is 0.75m from  each of the others.Calculate the  net force on each due to the other  two.
Pointcharges88μC,55μCand70μCareplacedinastraightline.Thecentraloneis0.75mfromeachoftheothers.Calculatethenetforceoneachduetotheothertwo.
Commented by NECx last updated on 08/Jul/18
Please give a diagram if necessary.  Thanks in advance.
Pleasegiveadiagramifnecessary.Thanksinadvance.
Answered by tanmay.chaudhury50@gmail.com last updated on 08/Jul/18
(F)_(−55) ^(88) =9×10^9 ×((88×10^(−6) ×(−55)×10^(−6) )/((^ 0.75)^2 )) forc on  Q=88μC by (−55μC)  attractive  (F)_(77) ^(88) =9×10^9 ×((88×10^(−6) ×70×10^(−6) )/((1.5)^2 ))   repulsi  so net firce on 88C by othdrs two charge is  (F)_(−55) ^(88) ∼(F)_(70) ^(88)   similar way other can be calculated
(F)5588=9×109×88×106×(55)×106(0.75)2forconQ=88μCby(55μC)attractive(F)7788=9×109×88×106×70×106(1.5)2repulsisonetfirceon88Cbyothdrstwochargeis(F)5588(F)7088similarwayothercanbecalculated
Commented by NECx last updated on 08/Jul/18
But the textbook says 53N,16N and  37.....Please can you enlighten me  on how they came about these results.
Butthetextbooksays53N,16Nand37..Pleasecanyouenlightenmeonhowtheycameabouttheseresults.

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