Question Number 41964 by Necxx last updated on 16/Aug/18
$${Prof}\:{Kintush}\:{has}\:{a}\:{near}\:{point}\:{of} \\ $$$$\mathrm{45}{cm}\:{and}\:{his}\:{far}\:{point}\:{is}\:{infinity}. \\ $$$${What}\:{type}\:{of}\:{lens}\:{and}\:{focal}\:{length} \\ $$$${should}\:{be}\:{recommended}\:{for}\:{his} \\ $$$${normal}\:{reading}? \\ $$
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
Answered by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18
$${taking}\:{reference}\:{from}\:{the}\:{attached}\:{comments} \\ $$$${this}\:{is}\:{hyperopic}\:… \\ $$$${lense}\:{should}\:{be}\:{converging}\:\:{that}\:{means}\: \\ $$$${bi}\:{convex}\:{lense}… \\ $$$${d}_{\mathrm{0}} =\mathrm{25}{cm}\:\:\:{d}_{\mathrm{1}} =−\mathrm{45}{cm} \\ $$$${f}=\frac{{d}_{\mathrm{0}} ×{d}_{\mathrm{1}} }{{d}_{\mathrm{0}} +{d}_{\mathrm{1}} }=\frac{\mathrm{25}×−\mathrm{45}}{−\mathrm{25}}=+\mathrm{56}.\mathrm{25}{cm} \\ $$$${p}=\frac{\mathrm{1}}{{f}\left({in}\:{meter}\right)}=\frac{\mathrm{1}}{\mathrm{0}.\mathrm{5625}}=\mathrm{1}.\mathrm{78} \\ $$$${pls}\:{check}… \\ $$
Commented by Necxx last updated on 17/Aug/18
$${wow}…{Thank}\:{you}\:{so}\:{much}\:{sir}\:{Tanmay} \\ $$$${please}\:{what}\:{pdf}\:{is}\:{this}\:{I}'{ll}\:{like}\:{to} \\ $$$${download}\:{it}\:.\:{It}\:{seems}\:{more}\:{explanatory} \\ $$$${than}\:{the}\:{others}\:{I}\:{have}. \\ $$