Prof-Kintush-has-a-near-point-of-45cm-and-his-far-point-is-infinity-What-type-of-lens-and-focal-length-should-be-recommended-for-his-normal-reading-

Question Number 41964 by Necxx last updated on 16/Aug/18

P r o f K i n t u s h h a s a n e a r p o i n t o f

45 c m a n d h i s f a r p o i n t i s i n f i n i t y .

W h a t t y p e o f l e n s a n d f o c a l l e n g t h

s h o u l d b e r e c o m m e n d e d f o r h i s

n o r m a l r e a d i n g ?

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Commented by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

Answered by tanmay.chaudhury50@gmail.com last updated on 16/Aug/18

t a k i n g r e f e r e n c e f r o m t h e a t t a c h e d c o m m e n t s

t h i s i s h y p e r o p i c \dots

l e n s e s h o u l d b e c o n v e r g i n g t h a t m e a n s

b i c o n v e x l e n s e \dots

d_{0} = 25 c m d_{1} = - 45 c m

f = \frac{d_{0} \times d_{1}}{d_{0} + d_{1}} = \frac{25 \times - 45}{- 25} = + 56.25 c m

p = \frac{1}{f (i n m e t e r)} = \frac{1}{0.5625} = 1.78

p l s c h e c k \dots

Commented by Necxx last updated on 17/Aug/18

w o w \dots T h a n k y o u s o m u c h s i r T a n m a y

p l e a s e w h a t p d f i s t h i s I^{'} l l l i k e t o

d o w n l o a d i t . I t s e e m s m o r e e x p l a n a t o r y

t h a n t h e o t h e r s I h a v e .

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