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Question Number 92000 by student work last updated on 04/May/20
proof 0!!=1
$$\mathrm{proof}\:\mathrm{0}!!=\mathrm{1} \\ $$
Answered by $@ty@m123 last updated on 04/May/20
n!=n.(n−1)!  ⇒(n−1)!=((n!)/n)  Put n=1  ⇒0!=1
$${n}!={n}.\left({n}−\mathrm{1}\right)! \\ $$$$\Rightarrow\left({n}−\mathrm{1}\right)!=\frac{{n}!}{{n}} \\ $$$${Put}\:{n}=\mathrm{1} \\ $$$$\Rightarrow\mathrm{0}!=\mathrm{1} \\ $$

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