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proof-that-1-2-




Question Number 149485 by abdurehime last updated on 05/Aug/21
proof that 1=2??
proofthat1=2??
Answered by Olaf_Thorendsen last updated on 05/Aug/21
if A = B  A×A = A×B  A^2  = AB = BA  A^2 −B^2  = BA−B^2   (A+B)(A−B) = B(A−B)  A+B = B  2B = B  2 = 1
ifA=BA×A=A×BA2=AB=BAA2B2=BAB2(A+B)(AB)=B(AB)A+B=B2B=B2=1
Commented by cherokeesay last updated on 05/Aug/21
  you can only simplify A−B on both sides of the equality (5th line) when A≠B !  but A = B ⇒ A − B = 0 !!!  so you will have 0 of the sides of this equality !
youcanonlysimplifyABonbothsidesoftheequality(5thline)whenAB!butA=BAB=0!!!soyouwillhave0ofthesidesofthisequality!
Commented by peter frank last updated on 05/Aug/21
A+B=B  A=0
A+B=BA=0
Commented by Olaf_Thorendsen last updated on 05/Aug/21
Of course sir !  But in the real life 1 ≠ 2 too.
Ofcoursesir!Butinthereallife12too.
Commented by MJS_new last updated on 06/Aug/21
I remember someone here proved  i=(√(−1))=±1  but I don′t remember how... that guy was  seriously convinced... as I stated before:  those who know nothing must believe everything
Iremembersomeonehereprovedi=1=±1butIdontrememberhowthatguywasseriouslyconvincedasIstatedbefore:thosewhoknownothingmustbelieveeverything
Commented by MJS_new last updated on 06/Aug/21
...on the other hand  f(x)=(x/x)  lim_(x→0) f(x) =1 ⇒ (0/0)=1  g(x)=((2x)/x)  lim_(x→0)  g(x) =2 ⇒ (0/0)=2    (0/0)=1∧(0/0)=2 ⇒ 1=2 q.e.d.    now what′s you argument Mr. Peter Frank?
ontheotherhandf(x)=xxlimx0f(x)=100=1g(x)=2xxlimx0g(x)=200=200=100=21=2q.e.d.nowwhatsyouargumentMr.PeterFrank?
Commented by MJS_new last updated on 06/Aug/21
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Commented by iloveisrael last updated on 06/Aug/21
the other way    lim_(x→0) ((sin x)/x)=1=(0/0)  lim_(x→0) ((tan (4x))/(2x))=2=(0/0)  then 1=2
theotherwaylimx0sinxx=1=00limx0tan(4x)2x=2=00then1=2
Commented by Olaf_Thorendsen last updated on 06/Aug/21
1 = (√1)  1 = (√((−1)×(−1)))  1 = (√(−1))×(√(−1))  1 = i×i = i^2 = −1  1 = −1
1=11=(1)×(1)1=1×11=i×i=i2=11=1
Commented by mathmax by abdo last updated on 06/Aug/21
but its correct dans Z/2Z
butitscorrectdansZ/2Z
Commented by MJS_new last updated on 06/Aug/21
many people (maybe most people) forget that  the rules in R are different from those in C.  (we usually don′t have to think about the  differences between the rules of N, Z and Q  as we just “walk through” them while we  start to study)
manypeople(maybemostpeople)forgetthattherulesinRaredifferentfromthoseinC.(weusuallydonthavetothinkaboutthedifferencesbetweentherulesofN,ZandQaswejustwalkthroughthemwhilewestarttostudy)
Commented by ajfour last updated on 06/Aug/21
2^(nd)  step to 3^(rd)   step is not  allowed, there are certain  rules here that need be  followed..
2ndstepto3rdstepisnotallowed,therearecertainrulesherethatneedbefollowed..
Commented by peter frank last updated on 06/Aug/21
no argument sir.understood
noargumentsir.understood
Answered by puissant last updated on 06/Aug/21
a=b  ⇒ a^2 =ab  ⇒a^2 +b^2 =b^2 +ab  ⇒a^2 +b^2 −2ab=b^2 −ab  ⇒ 2a^2 −2ab = b^2 −ab car a=b  ⇒ 2a(a−b)=a(a−b)  ⇒ 2a=a soit 2=1...
a=ba2=aba2+b2=b2+aba2+b22ab=b2ab2a22ab=b2abcara=b2a(ab)=a(ab)2a=asoit2=1

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