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proof-that-the-equation-of-a-ellipse-at-a-center-0-0-is-x-2-a-2-y-2-b-2-1-




Question Number 148270 by abdurehime last updated on 26/Jul/21
proof that the equation of a ellipse at  a center(0.0)is (x^2 /a^2 )+(y^2 /b^2 )=1
proofthattheequationofaellipseatacenter(0.0)isx2a2+y2b2=1
Commented by abdurehime last updated on 26/Jul/21
i want the process of proof
iwanttheprocessofproof
Answered by Olaf_Thorendsen last updated on 26/Jul/21
This is the equation of an ellipse.  The ellipse is a circle C(O,a) in the  particular case b = a (excentricity  e = (c/a) = ((√(a^2 −b^2 ))/a) = 0).
Thisistheequationofanellipse.TheellipseisacircleC(O,a)intheparticularcaseb=a(excentricitye=ca=a2b2a=0).
Commented by abdurehime last updated on 26/Jul/21
yes you are right!    sorry
yesyouareright!sorry

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