Prove-by-mathematical-induction-that-2002-n-2-2003-2n-1-is-divisible-by-4005-

Question Number 85073 by Roland Mbunwe last updated on 18/Mar/20

P r o v e b y m a t h e m a t i c a l i n d u c t i o n t h a t

2002^{n + 2} + 2003^{2 n + 1} i s d i v i s i b l e b y 4005

Commented by MJS last updated on 18/Mar/20

{it}^{'} s true for n = 1 but {it}^{'} s wrong for n = 2, 3, 4

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