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Prove-or-disprove-For-any-extension-E-of-a-field-F-F-u-F-u-u-E-Where-F-u-is-a-smallest-subfield-of-E-containing-F-and-u-and-F-u-f-u-f-x-F-x-F-x-is-a-polynomial-ring-over-F-




Question Number 169989 by udaythool last updated on 13/May/22
  Prove or disprove:  For any extension E of a field F,  F(u)=F[u]    ∀ u∈E.  Where F(u) is a smallest subfield  of E containing F and u and  F[u]={f(u)∣f(x)∈F[x]}, F[x] is a  polynomial ring over F.
Proveordisprove:ForanyextensionEofafieldF,F(u)=F[u]uE.WhereF(u)isasmallestsubfieldofEcontainingFanduandF[u]={f(u)f(x)F[x]},F[x]isapolynomialringoverF.

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