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Prove-that-0-1-tcos-npitdt-1-n-1-n-2-pi-2-




Question Number 88170 by Ar Brandon last updated on 08/Apr/20
Prove that   ∫_0 ^1 tcos nπtdt=(((−1)^n −1)/(n^2 π^2 ))
Provethat01tcosnπtdt=(1)n1n2π2
Commented by jagoll last updated on 08/Apr/20
= ((t.sin nπt)/(nπ)) + ((cos nπt)/(n^2 π^2 )) ] _0^1   = ((sin nπ)/(nπ)) + ((cos nπ)/(n^2 π^2 )) − (1/(n^2 π^2 ))   =  (((−1)^n −1)/(n^2 π^2 ))
=t.sinnπtnπ+cosnπtn2π2]01=sinnπnπ+cosnπn2π21n2π2=(1)n1n2π2
Commented by Joel578 last updated on 08/Apr/20
for n ∈ N
fornN

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