prove-that-0-e-x-lnxdx-

Question Number 127775 by Bird last updated on 02/Jan/21

p r o v e t h a t \int_{0}^{\infty} e^{- x} l n x d x = - γ

Answered by Dwaipayan Shikari last updated on 02/Jan/21

\int_{0}^{\infty} e^{- x} l o g x d x = Γ^{'} (1) = ψ (1) Γ (1) = - γ